-.6x^2+3.7x+3=0

Solution for -.6x^2+3.7x+3=0 equation:

-.6x^2+3.7x+3=0

We add all the numbers together, and all the variables

-0.6x^2+3.7x+3=0

a = -0.6; b = 3.7; c = +3;
Δ = b2-4ac
Δ = 3.72-4·(-0.6)·3
Δ = 20.89
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(3.7)-\sqrt{20.89}}{2*-0.6}=\frac{-3.7-\sqrt{20.89}}{-1.2}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(3.7)+\sqrt{20.89}}{2*-0.6}=\frac{-3.7+\sqrt{20.89}}{-1.2}
$